Paper 2 Thermal Physics B Answers
Q1 Ideal gas equation
- V=nRT/p=0.240(8.31)(310)/(2.10×105)=2.94×10−3 m3. [2]
- N=nNA=0.240(6.02×1023)=1.44×1023. [2]
- ⟨Ek⟩=23kT=1.5(1.38×10−23)(310)=6.42×10−21 J. [2]
Q2 First law
- ΔU=850−320=530 J. [2]
- Temperature increases. [1]
- Some supplied energy leaves as work done by the gas; only the remainder increases internal energy. [2]
Q3 p-V work
- Wby=pΔV=1.50×105(3.0×10−3)=450 J. [2]
- Work done on the gas is −450 J. [1]
- Work by gas is the area under the pressure-volume graph for expansion. At constant pressure this area is a rectangle pΔV. [2]