Paper 1 Electric Fields Answers
| Q | Answer | Reason |
|---|
| 1 | A | Definition: E=F/q for a positive test charge. |
| 2 | B | Field direction is the direction of force on a positive test charge. |
| 3 | B | E=kQ/r2. |
| 4 | C | Potential is work done per unit positive charge from infinity. |
| 5 | B | Potential has magnitude and sign but no direction. |
| 6 | A | Same potential means ΔV=0, so W=qΔV=0. |
| 7 | C | Field is normal to equipotentials. |
| 8 | A | Uniform plate field uses E=V/d. |
| 9 | B | For a negative charge, the force is opposite to E. |
| 10 | A | ΔU=qΔV. |
| 11 | B | Coulomb law is inverse square. |
| 12 | B | Electric field is a vector. |
| 13 | C | Potential is scalar and signed. |
| 14 | C | Constant transverse acceleration gives parabolic motion. |
| 15 | A | Force is charge times field vector. |
| 16 | B | E=V/d. |
| 17 | A | Equivalent field units. |
| 18 | B | Closer field lines represent stronger field. |
| 19 | A | V=kQ/r for positive Q. |
| 20 | B | A small positive test charge defines field without strong disturbance. |